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Answer: D We know that For two years, CI – SI = P x (r/100)2 SI = (P x r x t)/100 (I) Let, the sum be Rs. P P x (8/100)2 = 384 => P = 384 x 100/8 x 100/8 => P = Rs.60000 SI = (60000 x 12 x 6)/100 = Rs.43200 = 43200 => Satisfies the given condition. (II) Let, the sum be Rs. P P x (8/100)2 = 288 => P = 288 x 100/8 x 100/8 => P = Rs.45000 SI = (45000 x 12 x 6)/100 = Rs.32400 = 32400 => Satisfies the given condition. (III) Let, the sum be Rs. P P x (8/100)2 = 192 => P = 192 x 100/8 x 100/8 => P = Rs.30000 SI = (30000 x 12 x 6)/100 = Rs.21600 = 21600 => Satisfies the given condition.
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