Answer: D We know that For two years, CI – SI = P x (r/100)2 SI = (P x r x t)/100 (I) Let, the sum be Rs. P P x (8/100)2 = 384 => P = 384 x 100/8 x 100/8 => P = Rs.60000 SI = (60000 x 12 x 6)/100 = Rs.43200 = 43200 => Satisfies the given condition. (II) Let, the sum be Rs. P P x (8/100)2 = 288 => P = 288 x 100/8 x 100/8 => P = Rs.45000 SI = (45000 x 12 x 6)/100 = Rs.32400 = 32400 => Satisfies the given condition. (III) Let, the sum be Rs. P P x (8/100)2 = 192 => P = 192 x 100/8 x 100/8 => P = Rs.30000 SI = (30000 x 12 x 6)/100 = Rs.21600 = 21600 => Satisfies the given condition.
20.11% of 159.99 + √99.97 ÷ 5.02 = ?
'Arman' and 'Malik' initiated a business venture with their individual investments. 'Arman,' who actively participated in the business, received Rs. 2,4...
(14.98% of 319.99) - 7.998 = √?
19.22 × 11.99 + 142.15 = ?
(23.95)2– (25.006)2+ (8.0099)2– (7.07)2= ? - (14.990)2
159.98% of 4820 + 90.33% of 2840 = ? + 114.99% of 1980
[(2/3 of 599.77) + (39.69% of 450.14)] ÷ [(5/8 of 399.79) - √120.91] = ?
(23.99)2– (17.99)2+ (1378.88 + 44.88) ÷ ? = 607.998
9.99% of 19.86% of 30.23% of (11999.84 × 9.68) = ?