Question
Vessel A contains 50% more milk than water, while Vessel
B contains 40% more water than milk. If the mixtures from Vessel A and Vessel B are combined in a 3:5 ratio, and the resulting mixture has 49 liters less milk than water, what is the total quantity of the final mixture?Solution
Answer: c Ratio of the milk and water in vessel A = 150:100 = 3:2 Ratio of the milk and water in vessel B = 100:140 = 5:7 Milk in vessel A = 3x * 3/5 = 9x/5 Water in vessel A = 3x * 2/5 = 6x/5 Milk in vessel B = 5x * 5/12 = 25x/12 Water in vessel B = 5x * 7/12 = 35x/12 (6x/5 + 35x/12) - (9x/5 + 25x/12) = 49 72x + 175x – 108x – 125x = 49 * 60 14x = 49 * 60 x = 210 Final Quantity of Mixture = 8 * 210 = 1680 litres
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