Question
Four years ago, the ratio of Ratnesh's age to Shivam's
age was 7:5. After 'x' years, the average age of Jivan, Ratnesh, and Shivam will be (x + 22). Jivan’s age two years ago is equal to Shivam's age one year from now. What is the sum of the current ages of Ratnesh and Jivan?Solution
Answer: C Present age of Ratnesh = 7a+4 Present age of Shivam = 5a+4 After x years average age is (x+22) at present average age is 22 According to question, J -2 = S + 1 J – S = 3 J – (5a+4) = 3 J = 5a+7 (7a+4) + (5a+4) + (5a+7) = 22*3 a = 3 Present age of Ratnesh = 7*3 + 4 = 25 years Present age of Jivan = 5*3 + 7 = 22 years Required sum = 25+22 = 47 years
(1120.45 ÷ 15.89) × 11.34 = ? × 4.78
9.992 + (5.01 × 4.98) + ? = 225.03
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
(1200.11 ÷ 39.79) × (√224.85 + √49.03) + 20% of 479.79 = ?
(3/7 of 1049.88 + 44.95% of 799.79) ÷ (√168.89 + 24.77% of 400.11) = ?
234.19 ÷ 17.92 - 12.19 × 7.5 + 44.92% of 119.96 = ?
19.89% of 449.67 + 14.67% of 299.89 - 9.89% of 99.79 = ?
(18.21)² - (12.9)² = 20% of 649.9 - ? + 400.033
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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