A father is currently 3 times as old as his son. In 10 years, the father’s age will be twice that of his son. What are their present ages?
Let the son's current age be x years. Then the father's current age is 3x years. In 10 years, the father's age will be (3x + 10) and the son's age will be (x + 10). According to the problem: 3x + 10 = 2(x + 10) 3x + 10 = 2x + 20 x = 10 So, the son's current age is 10 years, and the father's current age is 30 years. Correct answer: a) Father: 30 years, Son: 10 years
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