Question
A father is three times as old as his son. Four years
ago, he was five times as old as his son. What are their present ages?Solution
Let the son's present age be x years. Then the father's present age = 3x. Four years ago, their ages were: Father = 3x - 4, Son = x - 4. According to the problem: 3x - 4 = 5(x - 4) 3x - 4 = 5x - 20 20 - 4 = 5x - 3x 2x = 16 x = 8. Now calculate their present ages: Son = 8 years Father = 3 * 8 = 24 years Correct option: c) Father = 24, Son = 8
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