A cuboid has dimensions 12 cm × 8 cm × 6 cm. If a cylindrical hole of diameter 4 cm is drilled through the entire length of the cuboid, what is the volume of the remaining solid? (π = 3.14)
Volume of the cuboid = l × b × h = 12 × 8 × 6 = 576 cm³. Volume of the cylindrical hole = π * r² * h Where diameter = 4 cm, so radius r = 2 cm and height h = 12 cm: Volume of the hole = π * (2²) * 12 = π * 4 * 12 = 48π cm³. Remaining volume = Volume of cuboid - Volume of hole = 576 - 48π. Using π = 3.14 Remaining volume = 576 - 150.72 = 425.28 cm³. Correct option: b) 425.28 cm³
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