Question

    A right circular cone has a base radius of 4 cm and a

    height of 9 cm. If a cylindrical hole of radius 2 cm is drilled through the axis of the cone, what is the volume of the remaining solid?
    A 12π cm³ Correct Answer Incorrect Answer
    B 20π cm³ Correct Answer Incorrect Answer
    C 15π cm³ Correct Answer Incorrect Answer
    D 22π cm³ Correct Answer Incorrect Answer

    Solution

    Volume of the cone = (1/3) * π * r² * h = (1/3) * π * (4²) * 9 = (1/3) * π * 16 * 9 = 48π cm³. Volume of the cylindrical hole = π * r² * h Where r = 2 cm and height of the cone = 9 cm: Volume of the hole = π * (2²) * 9 = π * 4 * 9 = 36π cm³. Remaining volume = Volume of cone - Volume of hole = 48π - 36π = 12π cm³. Correct option: a) 12π cm³

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