Question
A and B together can complete a task in 12 days. A alone
can complete the task in 20 days. In how many days can B alone complete the task?Solution
Let the total work be 60 units (LCM of 12 and 20). A's rate of work = 60 / 20 = 3 units/day. A and B together = 60 / 12 = 5 units/day. B's rate of work = 5 − 3 = 2 units/day. Time taken by B = 60 / 2 = 30 days. Thus, the correct answer is 30 days . Ans. a
`2/5` ___Â 15 ___Â 115___ 20 ___Â 4 = 581
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