Question
A can complete a work in 30 days, B in 24 days, and C in
20 days. A, B, and C work together for 5 days, after which B and C leave. How many more days will A take to complete the remaining work?Solution
Work done by A, B, and C together in 1 day = (1/30) + (1/24) + (1/20). LCM of 30, 24, and 20 is 120. Work done by A, B, and C in 1 day = (4 + 5 + 6)/120 = 15/120 = 1/8 of the total work. In 5 days, they complete 5/8 of the work. Remaining work = 1 − 5/8 = 3/8. A's rate of work = 1/30. Time taken by A to complete the remaining 3/8 of the work = (3/8) × 30 = 11.25 days. Ans. a
 If the numerator of a fraction is decreased by 20% and the denominator of the same fraction is increased by 30%, then what fraction of the old is the ...
There is a fraction whose denominator is 5 more than its numerator. If the numerator is increased by 10 and denominator is decreased by 4, the fraction ...
If the numerator of a fraction is increased by 40% and the denominator is decreased by 20%, then the value of the fraction becomes 21/16. Then tell the ...
The value of
Ravi has read 4/5 of a book while Saumya has read only 5/8 of the book she is reading. Both, however, have another 150 pages of their respective books r...
Numerator of a fraction is 4 less than the denominator. If 6 and 7 are added to numerator and denominator of a fraction respectively, then fraction beco...
- Find the fraction which is greater than (5/7) but less than (9/7).
0.0056 is equal to which of the following fractions?