Question
A rectangle has a length that is 4 cm more than its
width. If the perimeter of the rectangle is 32 cm, find the dimensions of the rectangle.Solution
Let width = x cm. Then, length = x + 4 cm. Perimeter = 2(length + width) = 32. 2[(x + 4) + x] = 32 → 2(2x + 4) = 32 → 2x + 4 = 16 → 2x = 12 → x = 6. Dimensions are length = 10 cm, width = 6 cm. Answer: a) Length: 10 cm, Width: 6 cm.
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