Two poles are 30 meters and 50 meters high, and the distance between their bases is 20√3 meters. Find the angle of elevation of the top of the taller pole as seen from the top of the shorter pole.
Let the height difference between the poles be 50 - 30 = 20 meters and the horizontal distance between them be 40 meters. Using the formula: tan(theta) = opposite/adjacent = 20/20√3 = 1/√3 So theta = 30° Correct option: b) 30°
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