A frustum of a cone has a lower base radius of 5 cm, an upper base radius of 3 cm, and a height of 4 cm. What is the volume of the frustum?
Volume of the frustum = (1/3) * π * h * (R² + Rr + r²) Where R = 5 cm, r = 3 cm, and h = 4 cm: = (1/3) * π * 4 * (5² + 5*3 + 3²) = (1/3) * (22/7) * 4 * (25 + 15 + 9) = (1/3) * (22/7) * 4 * 49 = (616/3) cm³. Correct option: d) 616/3 cm³
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