Work done by the first man in 5 days = 5/12. Remaining work = 1 - 5/12 = 7/12. Work done by the second man in one day = 1/18. Days taken by the second man = (7/12) / (1/18) = 7/12 × 18 = 10.5 days. Answer: c) 10.5 days.
The greatest number of four digits which when divided by 5, 7, 9 leave remainders 3, 5, 7 respectively is:
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