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Volume of frustum = (1/3)πh(r1² + r2² + r1r2) = (1/3) × 3.14 × 9 × (4² + 6² + 4 × 6) = (1/3) × 3.14 × 9 × (16 + 36 + 24) = (1/3) × 3.14 × 9 × 76 = 715.9 cm³.
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