A container has 80 liters of a mixture of milk and water, with 60% milk. If 10 liters of water are added, what will be the new percentage of milk in the mixture?
Milk in the mixture = 60% of 80 = 48 liters. Water initially = 80 - 48 = 32 liters. After adding 10 liters of water, total water = 32 + 10 = 42 liters. New total mixture = 48 + 42 = 90 liters. New percentage of milk = (48/90) × 100 = 53.3%. Answer: b) 53.3%
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