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ATQ, Curved surface area of a cone = π × r × x {Where 'x' is the slant height and 'r' is the radius of the cone} x2 = 232 + (46/2)2 Or, x2 = 529 + 529 Or, x = 23√2 cm So, required area = π × 23 × 23√2 = 529π√2 cm2
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