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ATQ, Since, 'Arjun' beats 'Bishnu' by 600 metres in a 1500 metre race Therefore, distance covered by 'Bishnu' when 'Arjun' covers 1500 metres = 1500 - 600 = 900 metres Similarly, when 'Bishnu' covers 1500 metres, 'Chintu' covers = 1500 - 700 = 800 metres Therefore, distance covered by 'Chintu' when 'Bishnu' covers 900 metres = 800 X (900/1500) = 480 metres Now, when 'Arjun' covers 1500 metres, 'Chintu' covers 480 metres When 'Arjun' will cover 3000 metres i.e. (1500 X 2) , 'Chintu' will cover 480 X 2 = 960 metres Required distance by which 'Arjun' will beat 'Chintu' in a 3000 metres race = 3000 - 960 = 2040 metres
For the study purpose, the mean of the observations is 148 gm and standard deviation is 17.4 gm. Approximately, the coefficient of variation equals to:
Following two statements are related to regression coefficient
(I) Independent of the change of origin
(II) Independent of the change of scale
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For the recorded observation, the coefficient of variation is 0.2 and the variance is 16. The arithmetic mean is:
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The arithmetic mean of the following frequency distribution of number of accidents X on week working days is:
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The grouped data for the observation are as follows.
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Five persons A, B, C, D and E occupy seats in a row at random. The probability that A and B sit next to each other is: