Question
Pipe X requires 12 hours to fill
2/3 of a tank, whereas pipe Y can empty the entire tank in 24 hours. If both pipes are opened simultaneously, how long will it take to fill 75% of an empty tank?Solution
ATQ, Time taken by pipe ‘X’ to fill the tank completely = 12 × (3/2) = 18 hours Time taken by pipe ‘Y’ to empty the tank = 24 hours Let the capacity of the tank be 72 units Efficiency of pipe ‘X’ = 72/18 = 4 units/hour Efficiency of pipe ‘Y’ = 72/24 = 3 units/hour Therefore, time taken by pipes ‘X’ and ‘Y’ to fill 75% of the tank = {(0.75 × 72)/(4 – 3)} = 54 hours
- What will come in place of (?), in the given expression.
(12% of 250) + (30% of 400) = ? What will come in place of (?) question mark in the following expression.
5(1/4) + 3(1/2) - 2(1/8) = ?
(-251 × 21 × -12) ÷ ? = 158.13
1555.5 + 1000.8 – 1354.3 = ? + 52
135.37 – 50.24 + 629.09 – 199.50 = ? – 214.68 + 42.65
What value should come in place of (?) question mark in the given expression.
75% of 320 + 40% of 150 = ?
? = 2640 ÷ {(35% of 1240) – 170}
Simplify the expression:
(9x² - 25) / (3x + 5)
What will come in the place of question mark (?) in the given expression?
? = 90% of 25% of (40 × 200) + 300
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