Question
Pipe X requires 12 hours to fill
2/3 of a tank, whereas pipe Y can empty the entire tank in 24 hours. If both pipes are opened simultaneously, how long will it take to fill 75% of an empty tank?Solution
ATQ, Time taken by pipe ‘X’ to fill the tank completely = 12 × (3/2) = 18 hours Time taken by pipe ‘Y’ to empty the tank = 24 hours Let the capacity of the tank be 72 units Efficiency of pipe ‘X’ = 72/18 = 4 units/hour Efficiency of pipe ‘Y’ = 72/24 = 3 units/hour Therefore, time taken by pipes ‘X’ and ‘Y’ to fill 75% of the tank = {(0.75 × 72)/(4 – 3)} = 54 hours
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