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Let the present ages of A and B are 4x years and 7x years respectively. Age of B after six years = 7x + 6 years Age of C after six years = (7x + 6) × 3/2 = ‘10.5x + 9’ years Present age of C = 10.5x + 9 – 6 = ‘10.5x + 3’ years According to question: 4x + 7x + 10.5x + 3 = 3 × 44 21.5x + 3 = 132 21.5x = 129, x = 6 So the present age of A = 4 × 6 = 24 years Present age of C = 10.5 × 6 + 3 = 63 + 3 = 66 years So the desired difference = 66 – 24 = 42 years
28.95% of 924.78 + 1955% of 38.99 = ?
1025.08 + 1623.13 - 1784.91 + 2564.31 - 2897.98 = ?
18.22 × 11.99 + 154.15 = ?
A train takes 8 seconds to pass a dog running in the opposite direction to the train at a speed of 10 m/s. Given that the train i...
(14.66)2 + (343.84 ÷ 3.88 - 55.87) = ? + 91.23
1299.999 ÷ 325.018 × 24.996 = ?
(?)2 + 6.113 = 25.92 – 19.03
6527.83 - 4891.21 + 7423.46 + ? = 14520.34
(95.89% of 625.15 + 36.36% of 499.89) ÷ 6.02 = ? – 269.72
(44/25) ÷ (154/199.5) × 419.91 = ? – (11.11)3