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ATQ,
Let the length of the train be 'L' metres, Given, speed of the train = 144 km/hr = 144 X (5/18) = 40 m/sec So, the relative speed of train w.r.t the man = 40 - 20 = 20 m/sec ATQ, (L/20) = 9 So, 'L' = 180 metres Therefore, time taken by the train to cross a bridge of 120 meters: = {(180 + 120) /40} = 7.5 seconds
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