Question
The question consists of two statements numbered "I and
II" given below it. You have to decide whether the data provided in the statements are sufficient to answer the question. There are three gardens 'X', 'Y' and 'Z'. The average number of trees in 'X', 'Y' and 'Z' is 240. Find the number of trees in 'Y' is how much percent more or less than total number of trees in 'X' and 'Z'. Statement I: Number of trees in 'Z' is 'a' more than the number of trees in 'X' and the number of trees in 'Y' is 'a' more than that in 'Z'. Statement II: The difference between number of trees in 'X' and 'Y' is 60.Solution
Let the number of trees in 'X', 'Y' and 'Z' be 'p', 'q' and 'r' respectively.
So, sum of the number of trees in 'X', 'Y' and 'Z' = 240 X 3
So, (p + q + r) = 720
Statement I:
Given, (r - p) = a.......(I)
Or, (q - r) = a..........(II)
From (i) & (ii), We cannot determine the value of 'a'
So, data in statement I alone is not sufficient to answer the question.
Statement II:
Case I:
We have, q = p + 60
Case II:
We have, q = p - 60
But we do not have any other data.
So, data in statement II alone is not sufficient to answer the question.
From Statement I and Statement II:
So, 'r' = 240
So, p + q = 720 - 240 = 480
And q - p = 60
So, q = (480 + 60) /2 = 270
And 'p' = (480 - 60) /2 = 210
So, total number of trees in 'X' and 'Z' = 210 + 240 = 450
Number of trees in 'Y' = 270
So, required percentage = {(450 - 270) /450} X 100 = 40% less
The data in both statements I and II together is necessary to answer the question.
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