From I and III, Speed of the train = 600/20× 18/5 = 72 km/hr. Time = 1620/72 = 22*1/2 hrs. Arrival time = 10 am + 22*1/2hrs = 8.30 am. Statement I and III is sufficient to answer the question.
(60/15) × 25 + 15 2 – 18% of 200 = ? 2
{(3/8) + (5/6)} × 120 – 53 = ?
325934.78 + 78545.30 + 92.25 =?
Simplify: (x4 X x9 X x-6 X x5 X x-7).
A. x ⁷
B. x 1
<...72 + 122 - 25% of 600 = ?
Find the value of 5342.5 +543.45+54.345 +5.4345+0.54345.
`(256/6561)(1/4) = ?`
648 ÷ 36 × 49 – 1012 + 847 = ?
74% of 2840 + 80% of 1640 - ?= 47²