Quantity I: There are two types of animals in a pet shop. Some are puppies and some are kittens. Each kitten takes 8 biscuits and each puppy takes 11 biscuits. If 500 biscuits were eaten by 55 animals. Find the number of puppies?
Quantity II: A, B, C, D purchased a toffees of Rs. 56 the share of B + C + D is 460% of A and the share of A + C + D is 366.66% of B and the share of C is 40% of A + B + D. Find the share of D.
Quanity I: Let number of puppies = P & number of kitten = k So P+K = 55 & 11P+8K = 500 by Solving these 2 equations, P = 20 Quanity II: A+ B+C+D = 56 --- (i) B+C+D =460% of A = 4.6A ---(ii) So from (i) & (ii), 4.6A+A = 56 or 5.6A = 56 or A = 10 A+C+D =366.66% of B = 11B/3 ---(iii) So from (i) & (iii), 11B/3+B = 56 or 14B/3= 56 or B = 12 C =40% of (A+B+D) or A+B+D = 100C/40 = 5C/2 ---(iv) So from (i) & (iv), 5C/2+C = 56 or 7C/2= 56 or C = 16 So finally D = 56-A-B-C = 56 -10-12-16 = 56 - 38 = 18 So Quantity I > Quantity II
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