How many litres of liquid A was contained by the Can initially?
Quantity I: A Can contains a mixture of two liquids A and B in the ratio 7: 5. When 9 litres of mixture are drawn off and the Can is filled with B, the ratio of A and B becomes 7: 9 .
Quantity II: A Can contains a mixture of two liquids A and B in the ratio 4:1. When 10 litres of mixture are drawn off and the Can is filled with B, the ratio of A and B becomes 2: 3 .
Quantity I. Suppose the Can initially contains 7x and 5x litres of mixtures A and B respectively. Quantity of A in mixture left = 7x – 7/12 of 9 = 7x – (21/4) Litres Quantity of B in mixture left =5x – 5/12 of 9 = 5x – (15/4) Litres {7x – (21/4)} / {5x – (15/4) + 9 } = 7/9 (28x-21)/(20x+21) = 7/9 So 252x – 189 = 140x + 147 or x = 3. Or Quantity of A in the Can initially = 7x = 21 Quantity II. Suppose the Can initially contains x and 4x litres of mixtures A and B respectively. Quantity of A in mixture left = (4x-4/5 of 10) =(4x-8) litres Quantity of B in mixture left = (1x-1/5 of 10) = (x-2) liters (4x-8)/(x-2+10) = 2/3 Or 12x – 24 = 2x + 16 So x= 4. Or Quantity of A in the Can initially = 4x = 16 Hence, Quantity I > Quantity II
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