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For Quantity 1, Let the number be= x (x + 1/x) × 0.4 = x – 1/x 0.4x + 0.4/x = x – 1/x 0.6x = 1.4/x x2 = 1.4/0.6 = 7/3 x3 = (7/3)√(7/3) Q = [(7/3)√(7/3) – 7/3]/(7/3) × 100 = [√(7/3) – 1] × 100 = 52.75% For Quantity 2, Let the Income of Gopal be = 100 Rs., The Income of Ram will be = 1.2 × 100 = 120 Rs. Then, Income of Suresh = (100 + 120) × 0.32 = 220 × 0.32 = 70.4 R = (120 – 70.4)/120 × 100 = 41.33% = Q2 Therefore quantity 1 will be greater than quantity 2 Q1 > Q2
What is the possible weight of R?
Which of the following is not an example of protocol?
Which one is used to protect computers from viruses?
The primary mechanism for providing context for data is....................
Statements:
Some drives are laptops.
All laptops are keyboards.
No keyboard is a computer.
Conclusions:
I. ...
1. Index
2. Tittle
3. Introduction
4. Contents
5. Chapter
By interchanging the given two signs and numbers which of the following equation will be not correct?
× and ÷, 2 and 6
I. 7 – 4 × 3...
When the digits, which are odd in the number ‘84376529’ are decreased by 2 and the remaining digits are increased by 1, then what is the sum of 5