The combined average workforce of sites 'P' and 'Q' is 70 workers. The total number of female workers at both sites is 60, with their distribution between sites 'P' and 'Q' being in the ratio of 11:9, respectively. It is also given that site 'Q' has a total of 90 workers.
Quantity-I: The total number of male workers at site ‘P’
Quantity-II: The total number of male workers at site ‘Q’
ATQ, The combined average workforce of sites 'P' and 'Q' is 70 workers. Hence, the total workforce at both sites is: Total workforce = 70 × 2 = 140 workers Thus, the total number of workers at both sites 'P' and 'Q' is 140. We are also given that site 'Q' has 90 workers. Therefore, the number of workers at site 'P' is: Workers at site P =140 − 90 = 50 The total number of female workers is 60, and they are distributed between sites 'P' and 'Q' in the ratio 11:9. Let the number of female workers at site 'P' be 11x and at site 'Q' be 9x. So, we have: 11x + 9x = 60 20x = 60 x = 3 Thus, the number of female workers at site 'P' is: 11x = 11×3 = 33 And the number of female workers at site 'Q' is: 9x = 9×3 =27 Calculate the number of male workers at each site Site 'P': The total number of workers at site 'P' is 50, and the number of female workers is 33. Therefore, the number of male workers at site 'P' is: Male workers at P = 50−33 = 17 Site 'Q': The total number of workers at site 'Q' is 90, and the number of female workers is 27. Therefore, the number of male workers at site 'Q' is: Male workers at Q = 90−27 = 63 Hence, The number of male workers at site 'Q' is greater than the number of male workers at site 'P'. Therefore, Quantity I is less than Quantity II.
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