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ATQ, Let the total work be 120 units. {LCM (24 and 40) } So, efficiency of 'Aman' = (120/24) = 5 units/day And efficiency of 'Bhuvan' = (120/40) = 3 units/day Let the efficiency of 'Chintu' be 'p' units/day ATQ: (5 + p) × 5 = (5 + 3) × (5 × 1.375) Or, (5 + p) = 8 × 1.375 Or, 5 + p = 11 So, 'p' = 6 Also, efficiency of 'Chintu' = 6 units/day Quantity I: Time taken by 'Chintu' to finish the work alone = (120/6) = 20 days So, Quantity I = 20 days Quantity II: Work done by 'Aman' and 'Bhuvan' in first five days = 5 × (5 + 3) = 40 units And work done by 'Aman' and 'Chintu' in last 5 days = 5 × (5 + 6) = 55 units And work done by 'Aman' alone = 120 - (55 + 40) = 25 units So, 'Aman' worked alone for 25 ÷ 5 = 5 days So, 'Aman' worked for a total of (5 + 5 + 5) = 15 days So, Quantity II = 15 days So, Quantity I > Quantity II
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