Quantity I: Difference in amount after 1 year = ₹7,200 - ₹6,000 = ₹1,200. This difference represents 1 year of simple interest, so the interest per year is ₹1,200. Since this is simple interest, we calculate the rate as follows: Rate per annum = (1,200 / 6,000) * 100 = 20%. Quantity II: Using the compound interest formula: Amount = Principal * (1 + Rate / 100) ^ Time. Amount = 20,000 * (1 + 8/100)^2. Amount = 20,000 * (1.08)^2. Amount = 20,000 * 1.1664 = ₹23,328. Quantity III: Using the simple interest formula: Amount = Principal + (Principal * Rate * Time) / 100. 15,000 = Principal + (Principal * 10 * 3) / 100. 15,000 = Principal (1 + 0.3) = Principal * 1.3. Principal = 15,000 / 1.3 ≈ ₹11,538.5 Comparing the quantities: Quantity I = 20%, Quantity II = 23,328, Quantity III = 11,538. Answer: (B) Quantity I < Quantity III > Quantity II
116*2/3% of 18600 + 666*2/3% of 1290 = 457*1/7% of 1750 + 555*5/9% of 3150 + ?
Evaluate: (768÷16)×(125÷25)−(81÷9)×12
702 + 26 + 142 - 20% of 310 = ? - 15% of 420
22.5% of 300 + 32.5% of 4500 =?
1200% of 18 + √1600 + 62 = ?2 + (90 of 0.4)
If 5√3+ √243 = 24.249, then what will be the value of √192+ 15√3.
412 - 352 + ? = 113 - 192
The valueof2 of5– 1/2 −[4÷2– 1/3 −{3/4−(5– 1/2 – 3/4 )}]is :
{(420 ÷ 28)% of 1400} ÷ 7 = ?