Question
If (y/5) =Â 11/(z+1). Value of 'y' is root of
p2 - 10p + 25 = 0. Quantity I: Value of 10z. Quantity II: 100 In the question, two quantities I and II are given. You have to solve both the quantities to establish the correct relation between Quantity-I and Quantity-II.Solution
ATQ, The quadratic equation is p2 −10p + 25 = 0. Solving for p:  
Use the given relation to find 'z'.
From (y/5) = 11/(z+1) =Â
Calculate Quantity I = Quantity I = 10z = 10 × 10 = 100
Compare Quantity I and Quantity II = Quantity I = 100 and Quantity II = 100
Hence, Quantity-I = Quantity-II or No relation .
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