Question
Quantity I: In how many ways can
a committee consisting of 2 Managers and 5 Team Leaders be selected from a group of 7 Managers and 8 Team Leaders? Quantity II: How many distinct seven-letter arrangements, with or without meaning, can be formed using all the letters in the word "CASATAE"? In the question, two quantities I and II are given. You have to solve both the quantities to establish the correct relation between Quantity-I and Quantity-II and choose the correct option.Solution
ATQ, Quantity I: Desired number of ways = 7C2 × 8C5 = 21 × 56 = 1176 Quantity II: Total number of words = 7!/3! = 840 So Quantity I > Quantity II.
((0.1)3+ (1.8)3+ (1.1)3 - 0.3 ×1.8 ×1.1)/((0.1)2+ (1.8)2+ (1.1)2- (0.18)- ...
180 % of 45 + √144 × 8 = ?2  + 80 % of 70
Find the simplified value of the given expression.
(1/4) of {64Â - 28 x 15 + 13 x 16 - 12.5 of 122}
If x²y² + (1/ (x2y2)) = 83, then the value of xy – 1/xy is:
32% of 450 + 60% of 150 = ? × 9
What is the value of ‘x’ if x% of 720 added to {2160 ÷ x of 20} × 2 gives 180?
Find the value of the following expression:
372 ÷ 56 × 7 – 5 + 2
(1/5){(2/5) × 400 + 20% of 150} = ?Â
1280 ÷ 8 + 490 ÷ √49 + ? = 150 * 2