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Quantity I: Total amount after 3 years = P(1 + r/100n)^(nt) = 10000(1 + 0.05/1)^(1*3) = 10000(1.157625) = 11576.25. Quantity II: Total amount after 2 years = P(1 + r/100n)^(nt) = 12000(1 + 0.04/1)^(1*2) = 12000(1.0816) = 12979.20. Answer: A (Quantity I < Quantity II)
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