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ATQ, We have, p + 3 = (1/2) × (p - 3 + 2p - 6) Or, 2p + 6 = 3p - 9 Or, 'p' = 15 Quantity I: Present age of 'Chintu' = 2p - 6 = 2 × 15 - 6 = 24 years So, Quantity I = 24 years Quantity II: Average present age = (1/3) × (p - 3 + p + 2p - 6) = (1/3) × (4p - 9) = (1/3) × (4 × 15 - 9) = (51/3) = 17 years So, Quantity II = 17 years Therefore Quantity I > Quantity II
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