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    Question

    f(a) = a3┬а- 3a2┬а+ 3a - 4

    Quantity l: Determine the value of f(a) when a = 3? Quantity II: Determine the value of f(a) when a = -2.5? Quantity Ill: Determine the value of f(a) when a = l .5? For every question, evaluate the three provided quantities, compute their respective values, and analyze how they compare to each other.
    A Quantity I > Quantity II < Quantity Ill Correct Answer Incorrect Answer
    B Quantity I > Quantity II = Quantity Ill Correct Answer Incorrect Answer
    C Quantity I < Quantity II = Quantity Ill Correct Answer Incorrect Answer
    D Quantity I > Quantity II > Quantity Ill Correct Answer Incorrect Answer
    E Quantity I < Quantity II < Quantity Ill Correct Answer Incorrect Answer

    Solution

    ATQ, Quantity I: f(a)=3├Ч3├Ч3 - 3├Ч(3)2┬а+ 3├Ч3 - 4 when a = 3, Or, f(a) = 5 Quantity II: f(a)=(-2.5)3 -3(-2.5)2 + 3├Ч(-2.5) - 4 = -45.875 when a = -2.5 Quantity III: So, f(a)=(1.5)3 -3├Ч(1.5)2 + 3├Ч(1.5) - 4 = -2.875 So, Quantity I > Quantity II < Quantity III

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