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    Question

    In the following question, read the given statement and

    compare Quantity I and Quantity II on its basis. (Only quantity is to be considered) (2pq + y тАУ 4)1/4 = m2 тАУ 3y тАУ 1┬а Value of y for above equation is 20. Where p and q are roots of the equation : 2x2 тАУ 23x + 65 = 0 Quantity I : m2 + 5 Quantity II : 2pq┬а Consider only numeric value.
    A Quantity I > Quantity II Correct Answer Incorrect Answer
    B Quantity I < Quantity II Correct Answer Incorrect Answer
    C Quantity I тЙд Quantity II Correct Answer Incorrect Answer
    D Quantity I тЙе Quantity II Correct Answer Incorrect Answer
    E Quantity I = Quantity II or relationship cannot be established. Correct Answer Incorrect Answer

    Solution

    2x2 тАУ 23x + 65 = 0┬а 2x2 тАУ (10 + 13)x + 65 = 0 2x2 тАУ 10x тАУ 13x + 65 = 0 2x(x тАУ 5) тАУ 13(x тАУ 5) = 0┬а x = 5, 13/2 or 6.5 p/q = 5/6.5 or p/q = 6.5/5 Putting 20 in place of y we get, (2 * 5 * 6.5 + 20 тАУ 4)1/4 = m2 тАУ 3 * 20 тАУ 1 (81)1/4 = m2 тАУ 61 m2 = 3 + 61 = 64 m = 8 Quantity I : m2 + 5 = 82 + 5 = 69 Quantity II : 2pq = 2 * 6.5 * 5 = 65 Quantity I > Quantity II

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