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ATQ, 120 = 5 × t = 4 × (t + 3) 5t = 4t + 12 t = 12 Speed of Pawan = 120/12 = 10 m/s Speed of Qureshi = 120/(12 - 2) = 120/10 = 12 m/s Speed of Rittu = 120/(12 + 3) = 120/15 = 8 m/s Quantity I, Distance between Qureshi & Rittu, when winner finish the race = 300 - 300/12 × 8 = 300 - 200 = 100 m Quantity II, Distance between Pawan & Rittu, when winner finish the race = 320 - 320/10 × 8 = 320 - 256 = 64 m Hence, Quantity I > Quantity II
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