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ATQ, 120 = 5 × t = 4 × (t + 3) 5t = 4t + 12 t = 12 Speed of Pawan = 120/12 = 10 m/s Speed of Qureshi = 120/(12 - 2) = 120/10 = 12 m/s Speed of Rittu = 120/(12 + 3) = 120/15 = 8 m/s Quantity I, Distance between Qureshi & Rittu, when winner finish the race = 300 - 300/12 × 8 = 300 - 200 = 100 m Quantity II, Distance between Pawan & Rittu, when winner finish the race = 320 - 320/10 × 8 = 320 - 256 = 64 m Hence, Quantity I > Quantity II
5 10 30 150 950 11550
...1 5 36 343 ? 59049
...388, ?, 98, 49, 24, 15
There are 3 series, you have to find value of a, b, c and then establish relation among a,b,c.
19, 25, 45, a, 553, 2767
1560 760 360 160 6...
157, 159, 189, 319, ‘?’, 1 407 , 2749
28 57 172 689 ? 20677
...? + (55)2= (140)2– (80)2– 6278
5 4 29 24 185 ?
To find the Next number in the given series.
342 510 726 996 1326 ?
...43 ? 45 39 47 37
...