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For Quantity 1: Let total work be 60 units (LCM of 15, 20, 30). A + B’s 1 day work = 60/15 = 4 units B + C’s 1 day work = 60/20 = 3 units A + C’s 1 day work = 60/30 = 2 units Adding all: 2(A + B + C) = 4 + 3 + 2 = 9 ⟹ A + B + C = 4.5 units/day Total time taken = 60/4.5 = 13.33 days Quantity 1 = 13.33 days For Quantity 2: A’s 1 day work = 1/24, B’s 1 day work = 1/36, C’s 1 day work = 1/48 Total 1 day work = 1/24 + 1/36 + 1/48 = (6 + 4 + 3)/144 = 13/144 Total time = 144/13 = 11.08 days Quantity 2 = 11.08 days Correct option: a) Quantity 1 > Quantity 2
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