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Quantity-I: A number is increased by 20%. If the new number is 240, find the original number. Quantity-II: A second number is decreased by 10%. If the new number is 180, find the original number. Quantity-III: A third number is increased by 15%. If the original number is 150, find the new number. Solution: Quantity I: Let the original number be x. x + 20% of x = 240 x + (20/100) × x = 240 x × (1 + 0.2) = 240 1.2x = 240 x = 240 / 1.2 = 200 Quantity II: Let the original number be y. y - 10% of y = 180 y - (10/100) × y = 180 y × (1 - 0.1) = 180 0.9y = 180 y = 180 / 0.9 = 200 Quantity III: New number = 150 + 15% of 150 New number = 150 + (15/100) × 150 New number = 150 + 22.5 = 172.5 Comparing Quantity-I, Quantity-II, and Quantity-III: Quantity-I = 200 Quantity-II = 200 Quantity-III = 172.5 Now, comparing: Quantity-I = Quantity-II Quantity-II > Quantity-III Therefore, the correct pair of symbols is: A & B Correct answer: a
30, 39, 66, ? , 174, 255
121/? = ?/144
(21 × 51 + 81)/(9 × 14 - 30) = ?
[3/5 of (31 + 44) – 10] ÷ 7 = ?
50 ÷ 2.5 × 64 + ? = 1520
(25.111 % of 200) × 26 ÷ 12.99 – 18.88 × 15.82 + 150.33% of 3√ 4917 = ? – 200
...(200 + 50% of 120) ÷ (9 × 2) = ?
(43/10) + (4.2/1.2) - (2.7/3) = (?/4) + (2.7/6.0)
24 × ?2 – 11 × 4 = 1900