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Quantity I: n(s) = ¹⁶C₃ = (16× 15× 14)/(3× 2× 1) = 560 n(E) = ⁷C₃ = (7× 6× 5)/(3× 2× 1) = 35 P(E) = 35/560 = 35/560 = 1/16 Quantity II. n(s) = ¹⁶C₃ = (16× 15× 14)/(3× 2× 1) = 560 n(E) = ⁴C₁× ⁵C₁× ⁷C₁ P(E) = 140/560 = 1/4 Hence, Quantity I < Quantity II
{(80% of 650 + 25 × 12) – 20 × ?} = 760
x= √(4 × ∛(16 × √(4 × ∛(16 ×…… ∝)) ) )
37% of 810 – 32% of 460.5 = ?
Simplify the expression:
(9x² - 25) / (3x + 5)
42% of 400 + 38% of 800 + ?2 = 728
If x - 1/x = 9, then the value of x² + 1/ x² is:
[(40)2 ÷ 32 × 4] ÷ 50 = ?
Calculate the value of x2, if [(8 + 62) ÷ 4 of x + 2.5 × 5 = 42 + 20% of 10].
√2025 + √1024 - √1296 = 20% of ?