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Let money received by men and women be 5x and 4x respectively. As per the question, 5x + 4x = 7,20,000 ⇒ 9x = 7,20,000⇒ x = 80,000 ∴ Amount received by men = 80,000 × 5 = Rs. 4,00,000 and Amount received by women = 80,000 × 4 = Rs. 3,20,000 Let number of men = a and ∴ Number of women = 132 – a ∴ Amount received by each man = 400000/a and Amount received by each women = 320000/(132 - a) As per the question, ⇒ (400000/a)/(320000/(132- a)) = 3/2⇒ 400000/a × (132-a)/320000 = 3/2 ⇒ (5 ( 132-a ))/4a = 3/2⇒ 1320 – 10a = 12a ⇒ 22a = 1320 ∴ a = 60 ∴ Number of men = 60
I. 2x2 + 13x + 21 = 0
II. 3y2 + 34y + 63 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 17x² - 78x + 61 = 0
Equation 2: 19y² - 89y + 70 ...
I). p2 + 22p + 72 = 0,
II). q2 - 24q + 128 = 0
I. 2x² - 9x + 10 = 0
II. 3y² + 11y + 6 = 0
I. x2 – 10x + 21 = 0
II. y2 + 11y + 28 = 0
I. 6y2- 17y + 12 = 0
II. 15x2- 38x + 24 = 0
I. 2b2- 37b + 143 = 0
II. 2a2+ 15a - 143 = 0
I. 6x2- 47x + 77 =0
II. 6y2- 35y + 49 = 0
I. 4 x ² - 4 x + 1 = 0
II. 4 y ² + 4 y + 1 = 0
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