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Let annual salary of P, Q and R two years ago be 4x, 3x and 5x respectively. Present salary of P = Rs. 19,360 (given) ∴ 4x× 110/100×110/100 × 1/12 = 19,360 ⟹ 121x/300 = 19360 ∴ x = (19360 × 300)/121 ∴ x = Rs. 48,000 ∴ R’s annual salary two years ago = 5x = 5 × 48,000 = Rs. 2,40,000 p.a. ∴ R’s annual salary one years ago = 2,40,000 × 150/100 = Rs. 3,60,000 p.a. ∴ R’s monthly salary one year ago = 360000/12 = Rs. 30,000 p.m.
Select the correct mirror image of the given figure when the mirror is placed at PQ as shown below:
Select the correct mirror image of the given figure when the mirror is placed to the right of the figure.
Which answer figure will complete the pattern in the question figure?
Select the correct mirror image of the given combination when the mirror is placed to the right side of it along MN.
Select the correct mirror image of the given combination when the mirror is placed at ‘ MN ’ as shown.