Question
Two years ago the ratio of annual salary of three
friends P, Q and R is 4 : 3 : 5. Every year since then the salary of P, Q and R increases by 10%, 12% and 50% respectively. If the present monthly salary of P is 19,360, then what was the monthly salary of R one year ago?Solution
Let annual salary of P, Q and R two years ago be 4x, 3x and 5x respectively. Present salary of P = Rs. 19,360 (given) ∴ 4x× 110/100×110/100 × 1/12 = 19,360 ⟹ 121x/300 = 19360        ∴ x = (19360 ×  300)/121 ∴ x = Rs. 48,000 ∴ R’s annual salary two years ago = 5x = 5 × 48,000 = Rs. 2,40,000 p.a. ∴ R’s annual salary one years ago = 2,40,000 × 150/100 = Rs. 3,60,000 p.a. ∴ R’s monthly salary one year ago = 360000/12 = Rs. 30,000 p.m.
√10404 + √9604 - ∛1728 - ∛42875 = ?
1299.999 ÷ 325.018 × 24.996 = ?
24% of 400 × 16% of ? = 384
Determine the simplified value of the given mathematical expression.
What will come in the place of question mark (?) in the given expression?
(144 × 16 ÷ 12) × 6 = ?Â
82% of 400 + √(?) = 130% of 600 - 85% of 400
192.251 + 326.233 + 125.021 + 19.273 = ?
45% of 360 - 160 + ? = √324
(160 × 12 - 13 × 20)/(120 × 2 + 2 × 35 + 2 × 11) = ?
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