Question
The cost of diamond varies directly as the square of its
weight. A diamond broke into four pieces with weights in the ratio 3 : 4 : 5 : 6. if the loss in the total value of the diamond was Rs. 119,000. The price of the original diamond was?ΒSolution
Let the weight of the pieces of diamond be 3x, 4x, 5x, 6x Total weight of diamond = 3x + 4x + 5x + 6x = 18x Price β (weight)2 => Price = k(weight)2 ; where, K is constant Original price = k(18x)2 Price of pieces = (9kx2 + 16kx2 + 25kx2 + 36kx2) = 86kx2 Loss in price = 324kx2 β 86kx2 = 238kx2 which is given as 119,000 => 238kx2 = 119000 => kx2 = 500 Original price = 324kx2 = 324 x 500 = 162000
Β If 4x = 40, 3y = 33, what is the value of 6x + 4y?
I. 2yΒ² - 3y β 14 = 0
II. 3xΒ² - 7x + 4 = 0
If a quadratic polynomial y = ax2 + bx + c intersects x axis at a and Ξ², then
I. 7x + 8y = 36
II. 3x + 4y = 14
I. 4p² + 17p + 15 = 0
II. 3q² + 19q + 28 = 0
The equation x2 β px β 60 = 0, has two roots βaβ and βbβ such that (a β b) = 17 and p > 0. If a series starts with βpβ such...
I. x2 + 16x + 63 = 0
II. y2 + 2y - 15 = 0
I. 40 x² - 93 x + 54 = 0
II. 30 y² - 61 y + 30 = 0
I. x + 1 = 3β 9261
II. y + 1 = β 324
I. 35x² - 24x – 35 = 0
II. 72y² - 145y + 72 = 0
Relevant for Exams:
