If x runs are second by Rohit, y runs by Shreyas and z runs by Virat, then x : y = y : z = 4:3. If total number of runs scored by Rohit, Shreyas and Virat is 518, the find the number of runs scored by Shreyas?
⇒ x : y = 4:3 = 16 : 12 ⇒ y : z = 4:3 = 12: 9 ⇒ x : y : z = 16 : 12 : 9 Since total runs scored by Rohit, Shreyas and Virat = 518 ⇒ 16a + 12a + 9a = 518 ⇒ 37a = 518 ⇒ a = 518/37 = 14 Hence, Runs scored by Shreyas = 12 × 14 = 168
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