Question
300 is divided into two parts such that thrice of the
first part and twice of the second part are in ratio 21:16, respectively. Find the difference between the two parts.Solution
Let the first part be ‘a’ So, second part = ‘300 – a’ ATQ; [3a/{2 × (300 – a)}] = (21/16) Or, 8a = 7 × (300 – a) Or, 15a = 2100 Or, a = 140 So, first part = 140 And, second part = 300 – a = 160 Required difference = 160 – 140 = 20
More Ratio and proportion Questions
2807, 1400, 697, 346, 171, 84, 41, ?
What will come in place of the question mark (?) in the following series?
68, 76, 61, 85, ?, 98
56, 27, 14.5, 6.25, ?, 1.0625
42, 48, 60, 84, 132, ?
5 6 14 45 ? 925
...47, 72, 122, ?, 297, 422
25 54 ? 228 460 924
...4 9 28 99 ? 2105 12660
...64, 32, 48, 120, 420, ?
Find the missing character.
