Question
300 is divided into two parts such that thrice of the
first part and twice of the second part are in ratio 21:16, respectively. Find the difference between the two parts.Solution
Let the first part be ‘a’ So, second part = ‘300 – a’ ATQ; [3a/{2 × (300 – a)}] = (21/16) Or, 8a = 7 × (300 – a) Or, 15a = 2100 Or, a = 140 So, first part = 140 And, second part = 300 – a = 160 Required difference = 160 – 140 = 20
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