The ratio of speed A and B = 3:4 the ratio of time A and B = 4:3 ATQ-B takes 15 minutes less than A. 1 = 12 3 = 12×3 = 36 minute = 36/60 hours =3/5hours
120 × 195 ÷ 13 - ? = 162
140% of 1270 + 60% of 2085 = 1881 + ‘?’% of 287
1540 ÷ 7 - 184 ÷ 8 = ?
Select the correct combination of mathematical signs that can sequentially replace the * signs and balance the given equation.
42 * 7 * 64 * 11 * 6 *4
[3/5 of (31 + 44) – 10] ÷ 7 = ?
√10000 × √8100 - (50)² = √(?) + (80)²
150% of 850 ÷ 25 – 25 = ?% of (39312 ÷ 1512)
Find the HCF of 15x2 + 8x – 12, 3x² + x – 2, 3x² - 2x, 9x² - 12x + 4
(120 × ?)/(36 × 0.2) = 200
