The ratio of speeds of A and B is 3:4 and B takes 12 minutes less than A to reach the destination, how many hours will it take to reach the same place?
The ratio of speed A and B = 3:4 the ratio of time A and B = 4:3 ATQ-B takes 15 minutes less than A. 1 = 12 3 = 12×3 = 36 minute = 36/60 hours =3/5hours
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