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ATQ, Let the children be P, Q, R and S Sweets with P : Q : R= 3 : 7 : 11 Let the number of sweets be 3k, 7k and 11k Total sweets with three eldest girls child = 21k sweets with F and S = 3 × 21k = 63k Total sweets = (21k + 63k) = 84k Sweets with F : (P + Q + R + S) = 3 : 4 Total 7 units of sweets = 84 k 1 unit = 12k sweets with F = 3 × 12k = 36k sweets with S = (63k – 36k) = 27k 27 k = 81 → k=3 Total number of sweets = 84k = 84 × 3 = 252
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