A sum of Rs.1000 is divided among P, Q and R such that P gets Rs.150 more than Q. Q gets Rs.110 more than R. How much does R receive?
Let the amount of money received by Q be Rs x According to the problem, we have the following conditions: P + Q + R = 1000 Q = x, P = x + 150 & x - 110 = R So, According to the question, x + 150 + x + x - 110 = 1000 3x = 1000 - 40 x = 960/3 x = 320 Hence, Q gets Rs 320. Therefore, R gets Rs 320 - 110 = Rs 210
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