Question
A pouch holds an assortment of Rs. 2, Rs. 5, and Rs. 10
coins. These coins are in the ratio of 4:5:3 for Rs. 2, Rs. 5, and Rs. 10 coins, respectively. If the combined monetary value of these coins is Rs. 252, determine the total quantity of coins in the pouch.Solution
Let the number of Rs. 2 coins, Rs. 5 coins and Rs. 10 coins be '4a', '5a' and '3a', respectively. ATQ, 2 X 4a + 5 X 5a + 10 X 3a = 252 Or, 8a + 25a + 30a = 252 Or, 63a = 252 So, 'a' = 4 Therefore, total number of coins in the bag = '12a' = 12 x 4 = 48
- Find the simplified value of the given expression.

Find the simplified value of the given expression

((9.77)0- γ(0.1)γ(-1))/(γ(6/24 )γ(-1)Β Γ(3/2)3+ γ((-2)/6)γ(-1) ) = ?
...1111.25 × 9.05 + 2323.23 × 9.05 – 2121.37 ×9.05 =?
15.50% of 6240 β 426.31 = ?Β
8 Γ 25% of ? = 400
Simplify the following expressions and choose the correct option.
45% of 640 + (2/5 of 350) = ?
What will come in the place of question mark (?) in the given expression?
(20% of 820 β 56 + 11 Γ 8) 1/2 = ? β 62
24% of 400 × 16% of ? = 384