An alloy contains copper and zinc in the ratio 5 : 3 and another contains copper and tin in the ratio 8 : 5. If equal weights of the two are melted together to form a 3rd alloy, find the weight of tin per kg in the new alloy.
To avoid fractions, take the LCM of 5 + 3 and 8 + 5. If 104 kg of each alloy are mixed, weight of tin in the alloy = 
Weight of tin per kg of 3rd alloy =
(15.87% of 79.98 + 19.69% of 64.22) × 4.83 = ?
25.22 of 359.98% + 499.99 ÷ 25.18 = ?
(20.23% of 780.31) + ? + (29.87% of 89.87) = 283
√31684.11 × √728.9 – (19.02)2 = ? × 4.99
960.11 ÷ 23.98 × 5.14 – 177.9 = √?
49.99% of 5400 + 923=?
[15.87% of 599.97 + 40.08 × ?] ÷ 4.04 = 8.082.02
(?)2 + 4.113 = 24.92 – 32.03
(2220.23 ÷ 36.98) + (768.32 ÷ 23.9) + 1644.11 = ?
74.856% of 639.98 - 15.098 of √145 = ? of 14.972
