The ratio of number of balls in bag A and bag B is 6:8 respectively. If six balls are transferred from bag B to bag A, then number of balls are equal in each bag. Find the number of balls in bag B initially?
Let number of balls in bag A be 6x and in bag B be 8x. As per the question, 8x - 6 = 6x + 6 ⇒ 8x - 6x = 6 + 6 ⇒x = 6 No. of ball in bag B = 8x = 8 × 6 = 48 balls
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