A box contains the coins of 5p, 10p and 25p are in the ratio 3:4:6. If there is Rs. 82 in all, how many 10p coins are there?
Let the no. of 5p, 10p, 25 p coins be 3x, 4x & 6x respectively. Then sum of their values = Rs. [{5 x (3x/100) + 10 x (4x /100) + 25 x (6x/100)}] =Rs. [(15x/100) + (40x /100) + (150x/100)] =Rs. (15x + 40x + 150x/100) = Rs. (205x /100) Therefore, 205x /100 = 82 x = 82 x (100/205) x = 40 Hence the no. of 10p coins = 4x = 4 x 40 = 160
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